Wednesday

April 1, 2015

April 1, 2015

Posted by **mike** on Wednesday, May 16, 2007 at 9:29pm.

1.(5n/3)- (4n/3)

2.(3x/10)+(9x/10)

3.(n-2/n+4)+(8/[n+4])

4.(5m+8/[m-1]) - (m-3/[m-1])

5.(x^2/[x-1]) - (1/[x-1])

6.(4x+y/[2x+3y])-(2x -2y/[2x+3y])

7.(x^2+3x+2/[x^2-16] + (3x++6/[x^2-16])

8.7/(x-5) - (2+x/[x-5])

First, "(5n/3)- (4n/3)" is not "5n over 3

If the fractions have the same denominator, just do the required operations in the numerator.

(5n/3)- (4n/3) = n/3

Use the same principle for the remaining problems.

I hope this helps. Thanks for asking.

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