Posted by **patti** on Wednesday, May 16, 2007 at 8:47pm.

7(3x+4)=8(2x+5)+13

how would I start a equation like this would it be 21x+28=16x+40+13 ?

Yes, that is the way to start. Now collect the x's on one side.

so it would be 21x-21x=28=

28=-5+40+13

28+13=41

x=41

7(3x+4)=8(2x+5)+13

21x+28=16x+40+13

To get all the x values on one side and the other numbers on the other side, subtract 16x and 28 from

*both* sides.

I don't know how you got

That will leave you with a much different answer.

I hope this helps a little more. Thanks for asking.

## Answer This Question

## Related Questions

- Algerbra - how do you solve 7(3x+4)=8(2x+5)+13 expand the parenthesis...I will ...
- Intermediate Algebra - Am I going in the right track? 8x -1/x + 5x - 3/2x = 16x^...
- algerbra 1 - 5x+8+3x-x+5=6x-3 do I start like this 5x+3x-x or 5x+3x+8+5=6x-3 I ...
- inequality expresion - The cost of a long distant telephone call is $0.36 for ...
- algebra 2 - I am trying to factor the expression -8y^2+28y-60 but can't get an ...
- MATH - This problem makes no sence to me i tried it but i know i am completely ...
- Pre Cal - find the domains of the following functions: a) f(x)=x^20 b) g(x)=1/(x...
- Math - Simplify I came up with 5.5 (15x^5-21x^4+21x^2)/(3x^2 ) not sure if I did...
- Algebra - Is this right? 7(3x-2)=70 21x-14=70; 21x-14+14=70+14; 21x=84; x=4
- Algebra - Is this right? 7(3x-2)=70 21x-14=70; 21x-14+14=70+14; 21x=84; x=4

More Related Questions