I have a chart and I have to draw the structure,name the shape snd lable the bond angle of some compounds. I've done most of them but im stuck on a few so heres what I need.Please and thank you

structure of NF3
structure,shape and bond angle of TeCl2
bond angle of CCl4

CCl4 is symetrical so the bond angles are 109.5 degrees (actually, 109o28" but the 28 minutes is ALMOST a half (30/60) would be 0.5.
NF3 is tetrahedral electronic geometry or trigonal pyramidal molecular geometry. The F-N-F bond angle is 102o .
Some sites say TeCl2 does not exist but wikipedia has a m.p. and a b.p. listed for it. No structure and no bond angles. I would think the structure would be akin to H2S or SF2 which are AB2U2 type molecules which makes it tetrahedral electronic geometry or angular molecular geometry. The XTeX would be close to 900 I would think but I can't confirm that.
The H2S angle is 92 degrees, the H2Se is 91 and H2Te is 89.5. Note as the size increases the angle approaches 90.

I wrote 109o28" when I meant 109o28' . I called it minutes but " means seconds while ' means minutes.

To draw the structures and label the bond angles of the compounds you mentioned:

1. NF3 (Nitrogen Trifluoride)
- Start by drawing a central nitrogen atom (N).
- Place three fluorine atoms (F) around the central nitrogen atom, ensuring to distribute them as far apart as possible.
- The resulting structure should resemble a tetrahedron, with the nitrogen at the center and the three fluorine atoms in a triangular arrangement around it.
- The bond angle between the nitrogen and each fluorine atom is approximately 102 degrees.

2. TeCl2 (Tellurium Dichloride)
- TeCl2 is a bit more complex as there is limited information available regarding its structure and bond angles.
- Based on the assumption that it is similar to H2S or SF2, we can consider it as an AB2U2 type molecule.
- Begin by drawing a central tellurium atom (Te).
- Add two chlorine atoms (Cl) around the central tellurium atom, ensuring they are as far apart as possible.
- The structure would resemble a tetrahedron similar to NF3, but with one of the vertices empty.
- The bond angle between the tellurium and each chlorine atom would likely be close to 90 degrees, but exact values cannot be confirmed without further information.

3. CCl4 (Carbon Tetrachloride)
- Start by drawing a central carbon atom (C).
- Place four chlorine atoms (Cl) around the central carbon atom, ensuring they are evenly spaced.
- The resulting structure should have a regular tetrahedral shape, with the carbon at the center and the chlorine atoms forming a symmetric arrangement around it.
- The bond angle between the carbon and each chlorine atom in CCl4 is approximately 109.5 degrees.

Please note that the information provided for TeCl2 is based on assumptions and lacks confirmed data on its structure and bond angles.