A firefighter at street-level, 55.0 m away from a burning building, directs a stream of water from a fire hose at an angle of 35.0° above the horizontal. If the speed of the stream is 50.0 m/s, at what height will the stream of water strike the building?
I started by finding the x and y components separately:
Vox= 50cos35= 40.958 & Voy= 50sin35= 28.697. I thought that I should use:
Delta y= Voy(t) + (1/2)(9.81m/s)(t^2)
But I need time; can I find t with t= square root of 2(55)/(9.81) = 3.349sec? Is this correct?
vox= 40.9
voy= 28.7
You know horizontal distance, so solve for time
55=vox*time
Now, having time, solve for height
h= voyi*time - 1/2 g time^2
Thank you! The answer was correct.
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You're welcome! I'm glad I could help you with your physics problem. Understanding physics concepts can be challenging, especially if you have a professor who isn't very helpful. It's great that you found this website and that the explanations have been helpful to you.
Physics can be a difficult subject, but with practice and a good understanding of the concepts, it can become more manageable. It's important to break down the problem into smaller steps and use the known information to find the unknowns.
In this problem, you correctly found the x and y components of the velocity by using trigonometry. You then used the y component, along with the equation for displacement in the y direction, to find the time it would take for the stream of water to hit the building.
To find the height at which the stream of water strikes the building, you used the equation for displacement in the y direction again, but this time you solved for the height. You substituted the known values of the initial y velocity, time, and acceleration due to gravity, and found the answer.
It's important to remember that in physics, it's not just about finding the answer, but also understanding the steps and reasoning behind it. This will help you in solving similar problems in the future.
If you have any more questions or need further clarification, feel free to ask!