Wednesday

March 4, 2015

March 4, 2015

Posted by **Lancelot** on Wednesday, May 16, 2007 at 3:15am.

Use the parallel axis theorem

http://hyperphysics.phy-astr.gsu.edu/hbase/parax.html

to compute the moment of inertia about the new axis. Call it I'. The parallel axis theorem tells you how to relate I' to the moment of inertia about the center of mass, which is

I = (1/2) M R^2

In your case, the parallex axis theorem says that

I' = I + M (R/2)^2 = (3/4)MR^2

Finally, the kinetic energy is

(1/2) I' w^2

where w is the angular velocity, "omega"

I see now, Thanks.

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