Homework Help: CHEMISTRY

Posted by Jason on Monday, May 14, 2007 at 11:09am.

Wondering If I did this correctly so far
50.0 ml of a 0.0500 M solution of lead (II) nitrate is mixed with 40.0 ml of a 0.200 M solution of sodium iodate at 25°C. Calculate the Pb2+ and IO3- concentrations when the mixture comes to equilibrium. At this temperature the Ksp for lead (II) iodate is 2.6 x 10-13. (10 marks)

The balanced equation
Pb(NO3)2 + 2NaIO3 ==> Pb(IO3)2 + 2NaNO3
Pb(NO3)2 = (0.05L)(0.05M) = 2.5 x 10-3 mols.
NaIO3 = (0.04L)(0.2M) = 8.0 x 10-3 mols.
NaIO3 is in excess.
Now if this is correct what do I do next?

So far so good.
NaIO3 is is excess; therefore, determine mols Pb(IO3)2 pptd and mols NaIO3 remaining.(All of the Pb(NO3)2 will be consumed.) Then it becomes a common ion problem with Ksp.
You will have solid Pb(IO3)2 in a saturated solution of Pb(IO3)2 that also contains xx mols NaIO3. Calculate Pb^+2.

No one has answered this question yet.

Answer this Question

Related Questions

chem - I'm stuck on this one aswell... 50.0 ml of a 0.0500 M solution of ...
Chemistry - 50.00 mL samples of 0.200 mol/L potassium phosphate with an excess ...
Chemistry help!!! - The class will react 50.00 mL samples of .200 mol/L ...
Chemistry - You made 100.0 ml of a lead (II) nitrate solution for lab but forgot...
chemistry check 2 - I know you've read this question too many times already ...
Chemistry - If I have 50 mL of Lead(II) Nitrate, it is possible for me to ...
Chemistry - If 32.0 mL lead(II) nitrate solution reacts completely with excess ...
Chemistry - 7 grams of chloride was dissolved in water. 20 ml of lead(II)nitrate...
Chemistry - 7 grams of chloride was dissolved in water. 20 ml of lead(II)nitrate...
Chemistry - Assignment  Calculate the pH, pOH, [H+], and [OH&#...

For Further Reading

First Name:
School Subject:
Answer: