Tuesday

January 27, 2015

January 27, 2015

Posted by **Rashida** on Saturday, May 12, 2007 at 8:26am.

Calculate in which year the amount pumped will fall below 5000.

The amounts of oil pumped from an oil well in each of the years 2001 to 2004 formed a geometric progression with common ratio 0.9. The amount pumped in 2001 was 100000 barrels.

Calculate in which year the amount pumped will fall below 5000

The last term of a geometric series is given by L = ar^(n-1)where a = the first term, r = the common ration and n = the number of terms.

Here, 5000 = 100,000(.9)^(n-1)

.05 = =.9^(n-1)

log(.05) = =log(.9)(n-1)

-.13010299 = -.04575 (n-1)

28.433 = (n-1) making n = 29.433

Therefore, less than 5000 barrels will be pumped in the year 2031 (2001 + 30)

- math -
**jemen all for all**, Monday, May 6, 2013 at 2:03pmfuctard die in hell

**Answer this Question**

**Related Questions**

lube oil systems - With many lube oil systems, it is common to cool the oil ...

Maths - 1..The first 2 terms of a geometric progression are the same as the ...

Math - For some constants A and B, the rate of production, R(t), of oil in a new...

Calculus II - For some constants A and B, the rate of production, R(t), of oil ...

word-math problem - Assume that the amounts of oil produced by the first, second...

Geometric progression - The second term of a geometric progression is 12 more ...

math - 1) If the number 1,1/3,1/9, are terms of Geometric progression. Find its ...

Economics - In 1973, Members of the Oraganization of Oil-Exporting Countries (...

Science - Oil comes from __________ that is pumped up from under the ground. ...

Math (Geometric Progression) - 5 distinct positive reals form an arithmetic ...