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October 2, 2014

October 2, 2014

Posted by **Rashida** on Saturday, May 12, 2007 at 8:26am.

Calculate in which year the amount pumped will fall below 5000.

The amounts of oil pumped from an oil well in each of the years 2001 to 2004 formed a geometric progression with common ratio 0.9. The amount pumped in 2001 was 100000 barrels.

Calculate in which year the amount pumped will fall below 5000

The last term of a geometric series is given by L = ar^(n-1)where a = the first term, r = the common ration and n = the number of terms.

Here, 5000 = 100,000(.9)^(n-1)

.05 = =.9^(n-1)

log(.05) = =log(.9)(n-1)

-.13010299 = -.04575 (n-1)

28.433 = (n-1) making n = 29.433

Therefore, less than 5000 barrels will be pumped in the year 2031 (2001 + 30)

- math -
**jemen all for all**, Monday, May 6, 2013 at 2:03pmfuctard die in hell

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