Monday

July 28, 2014

July 28, 2014

Posted by **jimmy** on Saturday, May 12, 2007 at 3:06am.

about the x-axis.

surface area=

⌠ 2pi * f(x)*sqrt[1 + (f'(x))^2] dx from a to b

⌡

it's been 45 years since I used that formula.

I ended up with the integral of (2pi(4x + 4)^(1/2) dx from 0 to 1

looks pretty straighforward after this, let me know whether it worked out.

BTW, what level is this from, surely not highschool.

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