Posted by jimmy on .
Find the area of the surface obtained by rotating the curve y=sqrt(4x) from x=0 to x=1 about the -axis.
about the x-axis.
⌠ 2pi * f(x)*sqrt[1 + (f'(x))^2] dx from a to b
it's been 45 years since I used that formula.
I ended up with the integral of (2pi(4x + 4)^(1/2) dx from 0 to 1
looks pretty straighforward after this, let me know whether it worked out.
BTW, what level is this from, surely not highschool.