Posted by Anonymous on .
a busleaves a station at 1 pm, traveling west at an average rate of 44 mi/h. One hour later a second bus leaves the same station, traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
The distance traveled apart in the first hour si 44mi/hr * 1 hr.
The additional distance traveled after that hour is
44*t + 48*t
so, the total distance apart at time t is 44*1 + 44*t + 48*t
set that equal to 274mi, and solve for t.