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October 31, 2014

October 31, 2014

Posted by **maricela** on Wednesday, May 9, 2007 at 11:17pm.

Let H be the height and L the length. The width is W = 8 and the base area is LW . Since the volume must be 72, HLW = 8 HL = 72

Therefore L = 9/H. You can treat H as the single unknown.

Cost = 10(2 HW + 2HL) + 20 WL

= 10(16 H + 18) + 1440/H

For minimum cost, d(Cost)/dH = 0

160 -1440/H^2 = 0

H = 3 meters

W= 8 meters

L = 9/H = 3 meters

Although you listed your subject as just "math". I had to use calculus to do this. I hope you were able to follow the solution.

thanx fo rthe help.

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