Posted by **Tina** on Wednesday, May 9, 2007 at 2:11pm.

Solve each of the following quadratic equations.

can some explain how to do these kinds of problems

4x^2=13x+12

i believe if i am understanding this i am supose to add to where i get =0

4x^2-13x+12=0

now what do i need to do

I am thinking factoring but I am not sure how to do this part

your equation should have been

4x^2 - 13x - 12 = 0

It does factor, I will give you a hint:

one of the factors is x-4

You must have been taught at least one general method to factor those quadratics that do factor.

It has been a while since i worked with any algebra

but i think i can remember some so this is what i got see if i am correct please

4x^2-13x-12=0

(4x+3)(x-4)=0

4x+3=0 0r x-4=0

4x=-3

4x/4=-3/4

x=-3/4

x-4=0

x=4

(-3/4,4)

did i do this right

yes, good for you.

it seems to be correct

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