Posted by Anonymous on .
A submerged submarine alters its buoyancy so that it initially accelerates upward at 0.325 m/s^2. What is the submarine's average density at this time? (Hint: the density of sea water is 1.025*10^3 kg/m^3).
The difference of densities will give you the net bouyant force on the sub per m^3. Assume a volume V for the sub.
Mass sub= V*density sub
Bouyant force= bouyantforce/m^3 * V
acceleration=bouyantforce/masssub
This ignores the friction of the water, which is considerable in real life.

physics 
micha,
9.92x10^2