How do u do logarithms where there is a log on one side and a number on the other...
Example-
-21.044=log(P/30)
I don't want just an answer to the example, i need to know how to do it please...
convert your log equation into an exponential equation.
-21.044=log(P/30) <------> 10^-21.044 = p/30
almost zero = p/30
p = almost zero
To solve a logarithmic equation like the one you provided, you need to convert it into an exponential equation.
In your example, the equation is:
-21.044 = log(P/30)
To convert this to an exponential equation, you can rewrite it as:
10^(-21.044) = P/30
Now, to solve for P, you can multiply both sides of the equation by 30:
30 * 10^(-21.044) = P
You might need a calculator for this part. Evaluate 10^(-21.044), and then multiply the result by 30. This will give you the value of P.
It's important to note that in this specific case, the value of P will be very close to zero because 10^(-21.044) is extremely small.