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March 2, 2015

March 2, 2015

Posted by **help me plz** on Tuesday, May 8, 2007 at 9:11pm.

look at the post by anonymous at 8:55, it is almost the same as yours.

Do it the same way.

length= x+6

width=x

x(x+6)=11

x^2 + ^x =11

x^2+6x-11=0

(x-_)(x-_)

solve for x.

Then substute the x for the length and width.

- math -
**mohammed**, Saturday, June 7, 2014 at 5:16pml=6+x, w=x,a= 11cm2 , area of rectangle= length*width , 11CM2=X(X+6), X2+6X=11,X2+6X-11=0

- math -
**mohammed**, Saturday, June 7, 2014 at 6:21pml=6+x, w=x,a= 11cm2 , area of rectangle= length*width , 11CM2=X(X+6), X2+6X=11,X2+6X-11=0, I GOT - 43 AND 43 BY AX2+BX+C=0

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