Posted by help me plz on Tuesday, May 8, 2007 at 9:11pm.
the length of a rectangle is 6 cm more than its width. the area is 11 cm squared. find the length and width.
look at the post by anonymous at 8:55, it is almost the same as yours.
Do it the same way.
length= x+6
width=x
x(x+6)=11
x^2 + ^x =11
x^2+6x11=0
(x_)(x_)
solve for x.
Then substute the x for the length and width.

math  mohammed, Saturday, June 7, 2014 at 5:16pm
l=6+x, w=x,a= 11cm2 , area of rectangle= length*width , 11CM2=X(X+6), X2+6X=11,X2+6X11=0

math  mohammed, Saturday, June 7, 2014 at 6:21pm
l=6+x, w=x,a= 11cm2 , area of rectangle= length*width , 11CM2=X(X+6), X2+6X=11,X2+6X11=0, I GOT  43 AND 43 BY AX2+BX+C=0
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