Solve the polynomial x^2+35x+27
Is this polynomial equal to something?
Assuming it is equal to zero
x= (-35 +- sqrt (35^2 -4*27) )/2
To solve the polynomial x^2 + 35x + 27, we need to find the values of x that satisfy the equation. First, let's write the equation in the quadratic form: ax^2 + bx + c = 0. In this case, a = 1, b = 35, and c = 27.
Using the quadratic formula, which is derived from completing the square, we can find the values of x:
x = (-b ± √(b^2 - 4ac)) / 2a
Substituting the values into the formula, we get:
x = (-35 ± √(35^2 - 4*1*27)) / (2*1)
Now, let's simplify the equation:
x = (-35 ± √(1225 - 108)) / 2
x = (-35 ± √1117) / 2
Therefore, the two solutions to the quadratic equation x^2 + 35x + 27 = 0 are:
x = (-35 + √1117) / 2
and
x = (-35 - √1117) / 2