The length of a triangle is twice the width. The area is 32 square units. Find the length and width.

I have the length of the triangle=2x and the width=x...
so would the equation be 2x(x)=32
OR NO?

Assume the "length" is the height measured from some side we will call the "base" with width x. The height is in this case 2x. The area is
(1/2) x*2x = x^2 = 32
Therefore
x = sqrt 32 = 5.657 and
2x = 11.314

To solve for the length and width of the triangle, we can use the given information and apply the formula for the area of a triangle.

Let's assume the width of the triangle is represented by the variable "x." Since the length of the triangle is twice the width, we can express the length as "2x."

The area of a triangle is given by the formula A = (1/2) * base * height. In this case, the base is x and the height is 2x.

So, the area equation can be written as (1/2) * x * 2x = 32.

Simplifying this equation, we have x^2 = 32.

To find the value of x, we take the square root of both sides of the equation: x = √32.

Evaluating the square root of 32, we find that x is approximately 5.657.

To find the length, we multiply the width (x) by 2: length = 2 * 5.657 = 11.314.

Therefore, the width of the triangle is approximately 5.657 units, and the length is approximately 11.314 units.