The given actual molarity of sulfuric acid was .08M. How do I calculate the absolute error and percentage error?
Your question isn't complete? Did you experimentally measure the molarity? Or was it somthing else? If you measure the value experimentally, here is the percent error of the measurement.
experimental value is what you measured.
[(exp value - acutal value)/actual value]*100
To calculate the absolute error, subtract the actual molarity from the experimental molarity. In this case, the actual molarity is given as 0.08M. Let's assume the experimental molarity is x.
Absolute Error = |x - 0.08|
To calculate the percentage error, divide the absolute error by the actual molarity and multiply by 100.
Percentage Error = (|x - 0.08| / 0.08) * 100
Please note that without the experimental value of the molarity, we cannot provide a specific numerical answer. You need to substitute the experimental value (x) into the above formulas to calculate the absolute and percentage errors.