The solubility of KCLO3 at 25 degree celcius is 10.9 per 100.g of h20.
question: If 15 g are addded to 100 g of water at 25 degree celcius with stirring, how much of KCLO3 will dissolve? Is the solution saturated, unsaturated, or supersaturated?
please help me with this quesiton. I don't get what's its asking but i do understand what saturated and unsaturated, and supersaturated means. tell me how to find out please. thank you.
From the solubility data, how much can go into solution? Answer is the amount given. Now, if you try to add more, how much goes into solution? All this is given in the problem statement.
To find out how much KCLO3 will dissolve in the given scenario, we need to compare the amount of KCLO3 added with the solubility of KCLO3 at 25 degrees Celsius, which is given as 10.9 g/100 g of water.
In this case, 15 g of KCLO3 is added to 100 g of water. Since we are given the solubility in terms of grams of KCLO3 per 100 g of water, we can calculate how much KCLO3 would dissolve in 100 g of water.
Using a proportion, we can set up the following equation:
(solubility of KCLO3 / 100 g of water) = (x g of KCLO3 / 100 g of water)
We can cross multiply and solve for x:
(solubility of KCLO3) * (100 g of water) = (x g of KCLO3) * (100 g of water)
Now inserting the given values:
(10.9 g/100 g of water) * (100 g of water) = (x g of KCLO3) * (100 g of water)
Simplifying the equation:
10.9 g = x g
Therefore, x = 10.9 g
This means that 10.9 g of KCLO3 will dissolve in 100 g of water at 25 degrees Celsius. However, in the given scenario, 15 g of KCLO3 is added to 100 g of water. Since the amount added is greater than the solubility, the solution is saturated.
A saturated solution is one in which the maximum amount of solute (in this case, KCLO3) has dissolved in the solvent (water) at a given temperature.
To summarize, 10.9 g of KCLO3 will dissolve in 100 g of water at 25 degrees Celsius. However, when 15 g of KCLO3 is added to 100 g of water, only 10.9 g will dissolve, making the solution saturated.