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October 1, 2014

October 1, 2014

Posted by **jessica** on Sunday, May 6, 2007 at 10:11pm.

Solve by substitution

4x-12y=5

-x+3y=-1

I know that you have solve one of the equations. I have picked the second one so it would be y= -1/3+1/3x right??

Then I substitute 4x-12(-1/3+1/3x)=5.

Now I have no clue what to do from there. Please help.

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.If that right?

In the bottom, rearrange to read

x= 3y+1

Now put that value for x in the top equation...

4x-12y=5

4( 3y+1)-12y=5

then solve for y.

when you get y, go back and put it in

x= 3y+1 to get x.

I suggest you show your number as

y=[(x-1)/3

Then 4x -12[(x-1)/3] = 5

Then 4x -4(x-1) = 5

etc. I'm sure you can handle it from here.

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