Posted by
**jimmy** on
.

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region.

2y=4x^1/2,y=5,2y+1x=5

Do you really mean "2y+1x=5" ?

It is not customary to use the coefficient 1 in front of a variable. It is unnecessary.

Since y=5 is one boundary, it would be easiest to integrate from the lowest y value of the region to y=5.

The equation "2y=4x^1/2"

would be better written as y = 2x^1/2