Wednesday

November 26, 2014

November 26, 2014

Posted by **Christian** on Friday, May 4, 2007 at 1:35pm.

x^2=49x^2-14x+1

Then solve for x.

48x^2-14x + 1=0

(8x-1)(6x-1)=0

and solve for two values of x that are possible.

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