Monday
April 21, 2014

Homework Help: chem

Posted by Ilene on Wednesday, May 2, 2007 at 5:41pm.

I'm stuck on this one aswell...

50.0 ml of a 0.0500 M solution of lead (II) nitrate is mixed with 40.0 ml of a 0.200 M solution of sodium iodate at 25C. Calculate the Pb2+ and IO3- concentrations when the mixture comes to equilibrium. At this temperature the Ksp for lead (II) iodate is 2.6 x 10-13

Write the balanced equation
Pb(NO3)2 + 2NaIO3 ==> Pb(IO3)2 + 2NaNO3
This is a Ksp problem with a common ion. You will need to determine the mols of each reactant from M x L = mols, see how much of the product is formed and which reactant is in excess. After you understand how to do a and b of the previous post you will know how to do this one.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry help!!! - The class will react 50.00 mL samples of .200 mol/L ...
Chemistry - You made 100.0 ml of a lead (II) nitrate solution for lab but forgot...
Chemistry - 50.00 mL samples of 0.200 mol/L potassium phosphate with an excess ...
chem - 15.0 mL of 0.30 M sodium phosphate solution reacts with 20.0 mL of 0.22 M...
CHEMISTRY - Wondering If I did this correctly so far 50.0 ml of a 0.0500 M ...
Chemistry - If 32.0 mL lead(II) nitrate solution reacts completely with excess ...
Chemistry - Assignment  Calculate the pH, pOH, [H+], and [OH] ...
chem. - Silver(I) nitrate and sodium sulfate react to form silver(I) sulfate and...
chemistry check 2 - I know you've read this question too many times already but ...
CHEM-KSP/KA PROBLEMS - really don't quite understand how to set up a ...

Search
Members