6x ^2 y^3+9x^2 y^3
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3x^2 y^2
how do I start to solve this
you need to distrubet
how do I do that is this right
6x^2 9x^2+y^3xy^3 ?
The terms on top are "like" terms so you can add them
then simplify
Can you see how the answer would be 5y ?
To simplify the expression (6x^2y^3 + 9x^2y^3) / (3x^2y^2), you need to distribute the numerator (6x^2y^3 + 9x^2y^3) over the denominator (3x^2y^2).
However, there is an error in your attempt. When distributing, you need to distribute each term of the numerator over the denominator. Let's break it down step by step:
1. First, distribute the first term of the numerator, 6x^2y^3, over the denominator 3x^2y^2. This would result in:
(6x^2y^3 / 3x^2y^2)
2. Next, distribute the second term of the numerator, 9x^2y^3, over the denominator 3x^2y^2. This would result in:
(9x^2y^3 / 3x^2y^2)
3. Now, simplify each term separately.
For the first term, when dividing the common factors, you subtract the exponents. In this case, the common factors are x^2 and y^2. So the first term simplifies to:
(6/3) * (x^2 / x^2) * (y^3 / y^2)
Simplifying further, you have:
(2) * (1) * (y^(3-2))
= 2y
For the second term, simplifying in the same way:
(9/3) * (x^2 / x^2) * (y^3 / y^2)
Simplifying further, you have:
(3) * (1) * (y^(3-2))
= 3y
4. Finally, add the simplified terms: 2y + 3y = 5y
Therefore, the simplified expression is 5y.