Sunday
August 30, 2015

Homework Help: calc

Posted by quita on Wednesday, May 2, 2007 at 4:15pm.

find the area of the region bounded by
y=4x, y=x^3, x=0 and x=2

Check this on paper, but in my mind I see the differential area (x^3-3x)dx

integrate that from 0 to 2

y=4x and y=x^3 intersect when x=-2,0 and 2
the vertical boundaries are x=0 and x=2, so
the area is the integral of 4x-x^3 from 0 to 2
which is [2x^2 - (1/4)x^4] from 0 to 2
=8-4 - 0
=4

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Members