Posted by **Kyle** on Wednesday, May 2, 2007 at 11:06am.

a force of 10 N holds an ideal spring with a 20-N/m spring constant in compression. The potential energy stored in the spring is..? 0.5J, 2.5J, 5.0J, 10J, or 200J?

POtential energy? Wouldn't it be 1/2 kx^2,

but x= F/k, so 1/2 kx^2= 1/2 k*F^2/k^2 and that can be reduced.

- physics -
**Anonymous**, Monday, March 28, 2011 at 9:11am
A 0.5-kg block attached to an ideal spring with a spring constant of 65N/m oscillates on a

horizontal frictionless surface. The total mechanical energy is 0.79 J. What is the greatest extension

of the spring from its equilibrium length?

- physics -
**hussam**, Monday, March 28, 2011 at 10:18am
square root of(.79/(.5*65))

- physics -
**Henry**, Monday, December 21, 2015 at 10:02pm
a. PE = 1/2 * kx^2.

or d = 10 * 1m/20N = 0.5 m.

PE = 0.5*F*d = 0.5 * 10 * 0.5 = 2.5 J.

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