Friday

July 25, 2014

July 25, 2014

Posted by **Mary** on Tuesday, May 1, 2007 at 9:05pm.

Distruive interference? Unless you put C in the line between A and B, this the asnwer is at infinity.

Now on the line between A and B, the distance from A to C has to be an odd multiple of halfwavelength greater than C to B. Now, the distance between the speakers is two wavelength. So if AC-BC is n lambda/2, then n must be one, so

AC=BC + 2.54/2 where BC= 5.8-AC

solve for AC.

Please tell me where I am going wrong.

AC = BC + 2.54/2

AC = 7.366

How come it's BC =5.8 - AC. Should it be BC= AC -5.8

because

AC = sqrt [(AB)^2 + (BC)^2]

AC = 5.8 + BC

How come it's BC =5.8 - AC? Shouldn't it be BC= AC -5.8

because

AC = sqrt [(AB)^2 + (BC)^2]

AC = 5.8 + BC

**Related Questions**

Physics. Please help!! - Distruive interference? Unless you put C in the line ...

physics - Two loudspeakers in a 20°C room emit 629 Hz sound waves along the x-...

physics - A student sets up two speakers spaced 2.5 meters apart, each playing ...

Physics - Two loudspeakers emit sound waves along the x-axis. The sound has ...

physics - Speakers A and B are vibrating in phase. They are directly facing each...

physics - Two speakers, one directly behind the other, are each generating a 579...

Physics - This question has me very lost. Two loudspeakers emit sound waves ...

physics - Two speakers are separated by distance d1 = 2.40 m and are in phase. ...

physics - Two speakers 14m apart are emitting tones at a frequency of 1020 Hz. ...

physics - Two loudspeakers emit sound waves along the x-axis. The sound has ...