Tuesday

March 31, 2015

March 31, 2015

Posted by **Mary** on Tuesday, May 1, 2007 at 9:05pm.

Distruive interference? Unless you put C in the line between A and B, this the asnwer is at infinity.

Now on the line between A and B, the distance from A to C has to be an odd multiple of halfwavelength greater than C to B. Now, the distance between the speakers is two wavelength. So if AC-BC is n lambda/2, then n must be one, so

AC=BC + 2.54/2 where BC= 5.8-AC

solve for AC.

Please tell me where I am going wrong.

AC = BC + 2.54/2

AC = 7.366

How come it's BC =5.8 - AC. Should it be BC= AC -5.8

because

AC = sqrt [(AB)^2 + (BC)^2]

AC = 5.8 + BC

How come it's BC =5.8 - AC? Shouldn't it be BC= AC -5.8

because

AC = sqrt [(AB)^2 + (BC)^2]

AC = 5.8 + BC

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