Posted by **Rachel** on Monday, April 30, 2007 at 9:13pm.

Hi, I would like to know if I did this problem correctly. Your help would be greatly appreciated!

"Chlorine, Cl2, is produced commercially by the electrolysis of aqueous sodium chloride. The anode reaction is

2Cl-(aq)---> Cl2(g) + 2e-

How long will it take to produce 2.45kg of chlorine if the current is 5.00 x 10^2A?

This is what I did:

2.45kg Cl2 x 1000kg/1kg Cl2 X 1 mol Cl2/70.9g Cl2 x 2 mol e-/1 mol Cl2 x 96,500C/1 mol e-

then I divided 5.00x10^2 from 6.67x10^7, and I got 133400 seconds.

I apologize if the steps I took look jumbled up since I typed it.

Thanks!

Looks ok to me and I get the 6.67E7 BUT when I divide that by 500 I obtain 13,338 seconds. That should be rounded, of course, but yout answer is 10x that. Try the arithmetic again.

I keep getting my same answer, 133,400. I don't know what I could be doing wrong!

I apologize. I get 6.67E6 for the first number and that divided by 500 = 13,338 seconds. The number is 6,669,252.468 on my calculator. See if you get that number. You may just be counting the places wrong which is what I did when I responded first with the E7 value.

## Answer This Question

## Related Questions

- Chemistry - 1.Chlorine gas can be produced commercially by passing an electric ...
- Chemistry - Chlorine gas + aqueous sodium bromide --> aqueous bromine + ...
- Chemistry - 1) A double displacement reaction takes place when aqueous sodium ...
- chemistry - sodium burns in chlorine to produce sodium chloride according to the...
- chemisrty - Consider the reaction between sodium metal and chlorine gas to form ...
- chemistry - sodium is manufactured commercially by electrolysis of molten sodium...
- chemistry - During the electrolysis of molten aluminum chloride in an ...
- chem - Balance the equation and answer in terms of moles. Chlorine gas can be ...
- Sciece (chemistry) - Sodium Chloride NaCl can be made by the reaction of sodium ...
- Chemistry ,Reactions at Electrodes during Electrol - Reactions at Electrodes ...

More Related Questions