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March 6, 2015

March 6, 2015

Posted by **Biggy Smalls** on Monday, April 30, 2007 at 11:28am.

Fe + O2---> Fe2O3.

Fe + O2 ==> Fe2O3.

Here is the way to balance these equations by inspection, meaning, by trial and error.

Rule #1. You may not change any subscripts. Equations are balanced by changing ONLY the coefficients.

Look on the right side and I see 2 Fe atoms. So we move to the left and place a 2 in front of the Fe.

2Fe + O2 ==> Fe2O3

Now look at the 3 O on the right. That is what we must have on the left. Two ways to approach this. I can balance it by placing 3/2 in front of the O2 like this.

2Fe + 3/2 O2 ==> Fe2O3. And the equation balances. Let's check it.

We have 2 Fe atoms on the left and right.

We have 3 O (3/2 * 2 = 3) atoms on the left and right.

Most of us like to see equations in whole numbers, not fractions, so we now multiply the entire equation by 2 to get rid of the 1/2.

4Fe + 3O2 ==> 2Fe2O3.

The second way: Starting with

2Fe + O2 ==> Fe2O3.

Look at O on the right and there are 3 atoms with two O atoms on the left. We know a whole numbrer coefficient won't work, so we trial and error. Knowing that 6 is a multiple of both 2 and 3, we just multiply Fe2O3 by 2 in order to have 6 O atoms on the right. And on the left we have a coefficient of 3 for O2.

2Fe + 3O2 ==> 2Fe2O3.

That gives us 6 O on the left and 6 on the right. Of course, it messed up the Fe but we can fix that easily. Since we now have 4 Fe on the right, we change the 2 for 2Fe on the left to 4Fe and the final equation is

4Fe + 3O2 ==> 2Fe2O3.

If your algebra is up to speed the balancing can also be done this way:

Fe + xO2 ==> yFe2O3

balancing Fe atoms

1=2y------------------(1

balancing O atoms

2x=3y------------------(2

for from equation (1

y=1/2

and substituting this in equation (2

2x=3(1/2)

so x=3/4

Replacing the symbols in the original

Fe + 3/4O2 ==> 1/2Fe2O3

but we are not allowed fractions so multiply through by 4

4Fe + 3O2 ==> 2Fe2O3

- chemistry -
**df**, Monday, September 3, 2007 at 6:09amwtf

- chemistry -
**Anonymous**, Thursday, January 8, 2009 at 7:39pmAg+

N2==>Ag3N

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