Posted by **Gabriela** on Monday, April 30, 2007 at 12:41am.

How can I find the horizontal asymptote of:

y=e^x/(2e^x+5)

i know you have to do the limit as x approaches infinity... but that is about all i know...

mulitply the numberator and denominator by e^-x

y= e^0/(2e^0 + 5e^-x)

y= 1/(2 + 5e^-x)

now, take lim as x >> int. Notice the e^-x goes to zero.

y= 1/2 as x approaches zero.

## Answer this Question

## Related Questions

- math - Suppose the the limit as x approaches 6 to the left equals infinity. What...
- Calculus - Find limit as x approaches 1 5/(x-1)^2 A. 0 B. Negative infinity C. 5...
- General Calculus Question - How do you solve a limit when it approaches infinity...
- AP Calculus - A function g(x) has the following characteristics: 1) It is ...
- PLEASE HELP WITH CALCULUS!!! - A function g(x) has the following characteristics...
- Calculus - Find the horizontal asymptote of f(x)=e^x - x lim x->infinity (e^x...
- calculus - What is the limit of the function as x approaches infinity? 4x^4 - 4^...
- Calculus - Evaluate the limit, if it exists. lim (sqrt(x+2) -3)/(x-7) (x -> 7...
- calculus - what is the answer for the integral of (1/(xln(x)) from 1 to infinity...
- Calculus - Find the limit as x approaches infinity of (lnx)^(1/x). This unit is ...