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December 7, 2016
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derivative
Posted by
Evan
on
Sunday, April 29, 2007
at 4:40pm.
q=(100/p+1)^2 - 1
what is q'?
use the chain rule:
q' = 2(100/p+1)(-100/(p^2))
i got
q' = 2(100/(p+1))(-100(p+1)^-2
=-2000/(p+1)^3
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