Posted by **jc** on Sunday, April 29, 2007 at 1:52pm.

i need help solvin this quadratic equation

2x^2+x-6=0

1/3x^2+8x-3=0

Try to factor, then set the factors equal to 0 to find possible solutions for x.

For the first one:

2x^2 + x - 6 = 0

Factors are:

(2x - 3)(x + 2) = 0

Setting the factors equal to 0:

2x - 3 = 0; x = 3/2

x + 2 = 0; x = -2

I hope this will help and is what you were asking.

## Answer this Question

## Related Questions

- MATH - HOW DO I SOLVE A QUADRATIC EQUATION BY FACTORING? Do you have a specific ...
- Math - -x^3 + 1.85x^2 - x +0.15 = 0 how can you solve for x? An exact solution ...
- Maths - 1) Factorise x2 -6x +8 (the 2 is squared) 2) Hence solve this equation: ...
- help...solving a polynomial....algebra - solve this please....help me....12x(...
- algebra II - How do you know if a quadratic equation will have one, two, or no ...
- algebra II - How do you know if a quadratic equation will have one, two, or no ...
- Math Please Help me!!! - 3x^2+17x+10 *You have to factor completley but I don't ...
- ALGEBRA - Find all positive values for k for which each of the following can be ...
- algebra - solve for x (24+2x)(10+2x) - 240 = 152 First multiply. 24(10) = ___ 2x...
- Math - Solve the given quadratic equation exactly using the quadratic formula. ...

More Related Questions