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January 27, 2015

January 27, 2015

Posted by **jc** on Sunday, April 29, 2007 at 1:52pm.

2x^2+x-6=0

1/3x^2+8x-3=0

Try to factor, then set the factors equal to 0 to find possible solutions for x.

For the first one:

2x^2 + x - 6 = 0

Factors are:

(2x - 3)(x + 2) = 0

Setting the factors equal to 0:

2x - 3 = 0; x = 3/2

x + 2 = 0; x = -2

I hope this will help and is what you were asking.

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