Posted by **Coreen** on Sunday, April 29, 2007 at 1:26am.

Speakers A and B are vibrating in phase. They are directly facing each other, are 7.4 m apart, and are each playing a 72.0 Hz tone. The speed of sound is 343 m/s. On the line between the speakers there are three points where constructive interference occurs. What are the distances of these three points from speaker A?

m (nearest)

m (middle)

m (farthest)

Calculate wavelength. When the difference in distances from each speaker are multiples of wavelength, construtcive interference occurs. For instance, if the wavelenght were 1 meter, then when distance A (speaker A to the point) = distance B -+ n Lambda

n= 0, 1, 2, ... constructive interference occurs. The easy solution is in the center, n=0. I suspect you will find a +- 1 solution.

## Answer this Question

## Related Questions

- physics - A student sets up two speakers spaced 2.5 meters apart, each playing ...
- physics - Two speakers are separated by distance d1 = 2.40 m and are in phase. ...
- physics - A college student is at a concert and really wants to hear the music, ...
- physics - A college student is at a concert and really wants to hear the music, ...
- physics - A college student is at a concert and really wants to hear the music, ...
- Physics - Moe, Larry, and Curly stand in a line with a spacing of d = 1.40m . ...
- Physics - suppose that the separation between speakers A and B is 5.80 m and the...
- physics - Two speakers, one at the origin and the other facing it at x = 1.04 m...
- Physics - Both drawings show the same square, each of which has a side of length...
- physics - Two speakers, one directly behind the other, are each generating a 579...