Posted by **joe** on Saturday, April 28, 2007 at 11:03pm.

what is the solubility of silver carbonate in water in 25 degrees celcius if Ksp=8.4X10-12? i don't know what to do

Write the equation.

Ag2CO3(s) ==> 2Ag^+ + CO3^=

Ksp = (Ag^+2)(CO3^=)

Let x = solubility of Ag2CO3. At equilibrium,(Ag^+) = 2x; (CO3^=) = x. Plug those into the Ksp expression and solve for x. The answer comes out in mols/L. If you want grams, then M x molar mass Ag2CO3 = grams Ag2CO3.

Post your work if you get stuck.

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