Monday
April 21, 2014

Homework Help: chem

Posted by DrBob222 on Saturday, April 28, 2007 at 9:04pm.

Kw = KaKb. With this equation you can convert any Ka to Kb and the reverse.



Codeine (Cod), a powerful and addictive painkiller, is a weak base.
a) Write a reaction to show its basic nature in water. Represent the codeine molecule with Cod.
b) The Ka for its conjugate acid is 1.2 x 10^-8. What is Kb for the reaction written in a?
c) What is the pH of a .0020 M solution of codeine?

For a, I have:
Cod + H2O <==> HCod + OH-
For b, I'm a little confused. I know the conjugate acid is HCod. However, I don't know how to use that value to help me solve Kb.
I'm pretty sure I know how to solve C.

Any help is appreciated :)

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