Monday

December 22, 2014

December 22, 2014

Posted by **Harry** on Friday, April 27, 2007 at 7:47pm.

y=x^2-1/(x^2+3x+2)

please and thank you

y =(x^2-1)/((x+1)(x+2))

=(x-1)/(x+2)

we cancelled the (x+1)/(x+1) which is 0/0 for x=-1

so in our simplified expression when x=-1 y = -2

There is a "hole" at (-1,-2)

in the final expression the denominator cannot be zero, it is zero when x=-2

so the function is discontinuous at x=-2

so what are the points of discontinuity?

i thought that -1 and -2 were the pts of discontinuity

doesn't y=x^2-1/(x^2+3x+2)

=(x+1)(x-1)/(x-3)(x+1)

=x-1/x-3

since you factor it?

**Answer this Question**

**Related Questions**

math - Can someone please help me with these few problems here? Find the holes ...

calculus please help! - Which of the following functions f has a removable ...

Calculus (Discontinuities) - Suppose, f(x) = { (x - 1)^2 / x + 1 if x < 2 (x^...

calculus - Hi, I am lost on couple of problems and i was wondering if you could ...

clalc - Suppose h(x) = f (g(x)) and the graphs of f and g are shown below. ...

pre-calculus - st andrews golf course in st andrews scotland is one of the ...

Calculus - #1 - Suppose g(x)={1/x+1 if x<1 {2x-1 if x≥1 The best ...

Calculus (Discontinuity) - Suppose f(x) = [sin(x^2 - 4)]^ -1. Identify any ...

Calculus - #4 - Suppose g(x)={1/(x-2) if x<1 {2x-4 if x≥1 The best ...

Calculus - #3 - Suppose g(x)={1/(x-2) if x<1 {2x-3 if x≥1 The best ...