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January 31, 2015

January 31, 2015

Posted by **Harry** on Friday, April 27, 2007 at 7:47pm.

y=x^2-1/(x^2+3x+2)

please and thank you

y =(x^2-1)/((x+1)(x+2))

=(x-1)/(x+2)

we cancelled the (x+1)/(x+1) which is 0/0 for x=-1

so in our simplified expression when x=-1 y = -2

There is a "hole" at (-1,-2)

in the final expression the denominator cannot be zero, it is zero when x=-2

so the function is discontinuous at x=-2

so what are the points of discontinuity?

i thought that -1 and -2 were the pts of discontinuity

doesn't y=x^2-1/(x^2+3x+2)

=(x+1)(x-1)/(x-3)(x+1)

=x-1/x-3

since you factor it?

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