Posted by
**Don** on
.

I need help with

write the equation of the line which contains the point (0,negavtive 3),

or written ars(0, -3)

and whose slope is 4.

if you want the equation in the form

y = mx + b

sub in -3 for y, 4 for m, and 0 for x

for

-3 = 4(0) + b

so b = -3

equation: y = 4x -3

We could have noticed that (0,-3) is the y-intercept and have directly into

y = 4x - 3

using the formula, y - (-3) = 4(x-0)

so y + 3 = 4x

y = 4x - 3