The Boltzman formula is S=k In W. A perfect crystal has a molar entropy of 0 at absolute zero because.
W=O
W=1
W=Na
k=1
K=r/Na
Why don't you try substituting W = 0 and W = 1, take the ln and see what you get.
To find out why a perfect crystal has a molar entropy of 0 at absolute zero, let's substitute W = 0 and W = 1 into the Boltzmann formula S = k ln W, and see what we get.
- If we substitute W = 0, then S = k ln 0. However, the natural logarithm (ln) of 0 is undefined because it represents an infinite value. This implies that the entropy would also be infinite, which does not make sense physically.
- Now, let's substitute W = 1. In this case, S = k ln 1. The natural logarithm of 1 is 0 (ln 1 = 0). Therefore, if W = 1, the entropy S would also be 0.
This means that a perfect crystal has a molar entropy of 0 at absolute zero when W = 1.