# math

posted by
**help me again(last one)**
.

the height of a triangle is 4 inches greater than twice its base. the area of the triangle is 168 square inches. what is the base of the triangle?

Area=1/2 B*H= 1/2 B (2B+4)

solve for B

h = 4 + 2b

b = ?

A = (b*h)/2 = 168

168 = [b(4+2b)]/2

168 = (4b + 2b^2)/2

336 = 4b + 2b^2

2b^2 + 4b - 336 = 0

2(b^2 + 2b - 168) = 0

2(b-12)(b+14) = 0

b=12 and b=-14

Ignore the negative answer, negative distances have no real meaning.