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January 30, 2015

January 30, 2015

Posted by **Twinkle** on Thursday, April 26, 2007 at 5:01am.

if the final temperature is 28.5 degree, find the specific heat of the alloy.

can anyone please help me with this question?tips?

thanks!

The heat lost by the alloy while cooling to the equilibrium temperature,

M' C' (295 - 28.5) = 3.55*266.5 C',

equals the heat gained by the water and vessel,

(Mw*Cw + M C)(28.5 - 19).

Write that statement as an algebraic equation and the only unknown will be the specific heat of the alloy, C'. Solve for it.

Mw and Cw are the mass and specific heat of water

M and C are the mass and specific heat of aluminum.

M' and C' are the mass and specific heat of the alloy. The only unknown is C'

thank you!

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