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April 2, 2015

April 2, 2015

Posted by **jean** on Thursday, April 26, 2007 at 2:01am.

Add the entropy changes due to: (1) heating the ice to 0C, (2) melting the ice, (3) heatng the water from 0 to 100 C, and (4) Evaporating the liquid water. For (2) and (3), the entropy change is the heat transfered (the heat of fusion or vaporization) divided by the corresponding temperature. For (1) and (3), an integration must be performed, and the entropy change is Mass*C*ln (T2/T1), where T2 is the final temperature and T1 is the initial temperature

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