a rectangular plot of land has an area of 1050 m squared. its length exceeds its width by 5 m. find the length of the plot.
i got x(x+5) is tha right?
Area is LW, and in this case (w+5)w
In your rendition, x is width. Add five to get length when you solve.
-3=w+5
To find the length of the plot, we can use the given information and set up an equation based on the area.
Let's assume that the width of the plot is x meters.
According to the information given, the length of the plot exceeds its width by 5 meters, so the length would be (x + 5) meters.
The area of the plot is given as 1050 square meters, which can be expressed as:
Area = Length × Width
1050 = (x + 5) × x
Simplifying the equation:
1050 = x^2 + 5x
Rearranging the equation to the form:
x^2 + 5x - 1050 = 0
Now we can solve this quadratic equation to find the value of x, which represents the width of the plot.
You can either factorize the quadratic equation or use the quadratic formula to solve for x.
If we factorize the equation:
(x - 30)(x + 35) = 0
Setting each factor equal to zero:
x - 30 = 0 or x + 35 = 0
Solving for x:
x = 30 or x = -35
Since the width cannot be negative, we can discard x = -35. Therefore, the width of the plot is x = 30 meters.
To find the length, we add 5 to the width:
Length = x + 5 = 30 + 5 = 35 meters
So, the length of the plot is 35 meters.