Br2+AlI3

The Bromine will replace the Iodine in the Alumninum Iodide (AlI3), leading to I2 and AlBr3 as products. See if you can balance the reaction.

To balance the chemical equation, we need to ensure that the same number of each type of atom is present on both sides of the equation.

Here's a step-by-step process to balance the equation:

1. Write down the unbalanced equation:

Br2 + AlI3 → I2 + AlBr3

2. Start by balancing the non-hydrogen and non-oxygen atoms. In this case, we have bromine (Br), iodine (I), and aluminum (Al).

On the left side, we have 2 bromine atoms (Br2) and 3 iodine atoms (AlI3). On the right side, we have 2 iodine atoms (I2) and 3 bromine atoms (AlBr3).

3. Balance the non-hydrogen and non-oxygen elements one at a time. Let's start with bromine.

Since there are 2 bromine atoms on the left side and 3 bromine atoms on the right side, we need to place a coefficient of 3 in front of Br2. This results in the equation:

3 Br2 + AlI3 → I2 + AlBr3

Now, we have 6 iodine atoms on the left side and 2 iodine atoms on the right side.

4. To balance iodine, place a coefficient of 3 in front of I2:

3 Br2 + AlI3 → 3 I2 + AlBr3

5. Check if all the atoms are balanced.

On the left side, we have 6 bromine atoms, 3 aluminum atoms, and 9 iodine atoms. On the right side, we have 9 bromine atoms, 3 aluminum atoms, and 6 iodine atoms.

The equation is now balanced, with 6 bromine atoms, 3 aluminum atoms, and 6 iodine atoms on each side.

The balanced equation is:

3 Br2 + AlI3 → 3 I2 + AlBr3