posted by Brissa on .
How would you prepare 2.5 L of a 0.05 M solution of iron (III) chloride using iron (III) chloride hexahydrate?
Would you use the eqn,
Cinit x Vinit = Cfinal x Vfinal
So I have Cfinal and Vfinal... now what?
from 2.5 L of 0.05 M, how many of moles iron (III) chloride hexahydrate do you need?
Moles = volume x conc
then using number of moles
mass required = number of moles x (RMM of iron (III) chloride hexahydrate)
Then you dissolve this mass in water and make the volume up to 2.5 L.
What does the RMM mean?
Relative Molecular Mass