The area of a rectangle of length x is given by 3x^2+5x find the width of the rectangle
a=l*w
=x*(3x+5)
I stoped here I am not sure if I am correct i was taken the 3x+5 as the width and x as the length but i am not sure if the 3x+5 should be the area and divid by x the length could some one get me on the right track please
if the area is 3x^2 + 5x and the length is x, then the width must be the area divided by the length.
that is: 3x^2 + 5x ÷ x
which is indeed 3x + 5 like you had.
check: multiply x by 3x+5 .....
To find the width of the rectangle, you can divide the area of the rectangle by its length.
Given that the area of the rectangle is 3x^2 + 5x and the length is x, you can set up the equation as follows:
Width = Area / Length
Width = (3x^2 + 5x) / x
Now, you can simplify the expression by dividing each term by x:
Width = 3x + 5
So, the width of the rectangle is 3x + 5. You were correct in your initial interpretation.