Posted by **Mischa** on Monday, April 23, 2007 at 3:46pm.

A force of 250 N is required to stretch a spring 5m from rest. Using Hooke's law, F=kx, how much work, in joules, is required to stretch the spring 7m from rest?

The energy required scales with x^2.

Multiply 250 J by (7/5)^2.

- calc/physics -
**derek**, Wednesday, December 5, 2012 at 4:05pm
350 J

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