Tuesday
October 21, 2014

Homework Help: calc/physics

Posted by Mischa on Monday, April 23, 2007 at 3:46pm.

A force of 250 N is required to stretch a spring 5m from rest. Using Hooke's law, F=kx, how much work, in joules, is required to stretch the spring 7m from rest?

The energy required scales with x^2.
Multiply 250 J by (7/5)^2.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...
Physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...
Physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...
Physics - Hooke's law states that it takes a force equal to kΔx is required...
physics - The force required to stretch a Hooke’s-law spring varies from 0 N to ...
Physics - When a 2.00-kg object is hung vertically on a certain light spring ...
Physics - When a 3.00-kg object is hung vertically on a certain light spring ...
physics - When a 2.60-kg object is hung vertically on a certain light spring ...
science - It takes 3.38 J of work to stretch a Hooke’s-law spring 5.63 cm from ...
Physical Science - An exercise spring has a spring constant of 315 N/m. How much...

Search
Members