calculus
posted by mark on .
The base of a solid is a circle of
radius = 4
Find the exact volume of this solid if the cross sections perpendicular to a given axis are equilateral right triangles.
The equation of the circle is:
x^2 + y^2 = 16
I have the area of the triangle (1/2bh) to be equal to 2sqrt(12)
(1/2 * 4 * sqrt12)
there are triangles that have vertical bases. They run parallel to the yaxis. The triangles are inside of the circle
Any help would be greatly appreciated! Thanks!
The volume of a cone is
V =(1/3)*(base area)*(height)
In your equilateral case,
height = sqrt3 * r.
Therefore
V = sqrt3*pi*r^3

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