Wednesday

October 1, 2014

October 1, 2014

Posted by **mark** on Sunday, April 22, 2007 at 10:25pm.

radius = 4

Find the exact volume of this solid if the cross sections perpendicular to a given axis are equilateral right triangles.

The equation of the circle is:

x^2 + y^2 = 16

I have the area of the triangle (1/2bh) to be equal to 2sqrt(12)

(1/2 * 4 * sqrt12)

there are triangles that have vertical bases. They run parallel to the y-axis. The triangles are inside of the circle

Any help would be greatly appreciated! Thanks!

The volume of a cone is

V =(1/3)*(base area)*(height)

In your equilateral case,

height = sqrt3 * r.

Therefore

V = sqrt3*pi*r^3

**Answer this Question**

**Related Questions**

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...

calculus - The base of a solid is a circle of radius = 4 Find the exact volume ...

calculus - volume of solid whose base is a circle with radius a, and cross ...

College Calculus - Find the volume of the solid with given base and cross ...

calculus - the base of a solid is a region in the first quadrant bounded by the ...

Calculus - The base of a solid is the region enclosed by the graph of x^2 + 4y^2...

calculus - the region bounded by the quarter circle (x^2) + (y^2) =1. Find the ...

Calculus - The base of a certain solid is the triangle with vertices at (-14,7...