Friday
October 24, 2014

Homework Help: calculus

Posted by mark on Sunday, April 22, 2007 at 10:25pm.

The base of a solid is a circle of
radius = 4
Find the exact volume of this solid if the cross sections perpendicular to a given axis are equilateral right triangles.

The equation of the circle is:
x^2 + y^2 = 16

I have the area of the triangle (1/2bh) to be equal to 2sqrt(12)

(1/2 * 4 * sqrt12)

there are triangles that have vertical bases. They run parallel to the y-axis. The triangles are inside of the circle

Any help would be greatly appreciated! Thanks!


The volume of a cone is
V =(1/3)*(base area)*(height)

In your equilateral case,
height = sqrt3 * r.
Therefore
V = sqrt3*pi*r^3

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
Calculus - R is the region in the plane bounded below by the curve y=x^2 and ...
calculus - The base of a solid is a circle of radius = 4 Find the exact volume ...
calculus - volume of solid whose base is a circle with radius a, and cross ...
College Calculus - Find the volume of the solid with given base and cross ...
calculus - the base of a solid is a region in the first quadrant bounded by the ...
Calculus - The base of a solid is the region enclosed by the graph of x^2 + 4y^2...
calculus - the region bounded by the quarter circle (x^2) + (y^2) =1. Find the ...
Calculus - The base of a certain solid is the triangle with vertices at (-14,7...

Search
Members