Post a New Question


posted by on .

The base of a solid is a circle of
radius = 4
Find the exact volume of this solid if the cross sections perpendicular to a given axis are equilateral right triangles.

The equation of the circle is:
x^2 + y^2 = 16

I have the area of the triangle (1/2bh) to be equal to 2sqrt(12)

(1/2 * 4 * sqrt12)

there are triangles that have vertical bases. They run parallel to the y-axis. The triangles are inside of the circle

Any help would be greatly appreciated! Thanks!

The volume of a cone is
V =(1/3)*(base area)*(height)

In your equilateral case,
height = sqrt3 * r.
V = sqrt3*pi*r^3

  • calculus - ,


Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question