# Algebra

posted by
**Amanda** on
.

Find two consecutive odd integers such that 5 times the first integer is 12 more than 3 times the second. I've gotten this far but confused as to what the two intergers are.

5x=3(x+2)=12

5x=3x+2+12

5x=3x+14

2x=14

2x/2x=14/2

x=7

Let n be first integer, so n+2 is the second odd integer.

5n -12= 3(n+2)

5n= 3n+6 + 12

compare this to your work tofind the error.