Hi, I posted yesterday with this lab question.
"Calculate the molar amounts of NaOH used in the reaction with the HCl solution and with the HC2H3O2.
I think I got the answer to that with the help that I received. I had 5 mL of HCl, and I was using .100 M NaOH, so I got 5x10-4 mol of NaOH for that one. now for #2...
"Calculate the molar concentration (molarity) of the HCl solution and the HC2H3O2 solution."
Would I divide the 5.0x10-3L and divide that from 5.0x10-4L?
L x M = mols
0.005 x 0.1M = 5x10^-4 mols NaOH.
That is the mols HCl, too.
L x M = mols HCl
Plug in L and mols and calculate M.
Thank you very much! :)
Yes, you would divide the 5.0x10-3L by the 5.0x10-4L to calculate the molar concentration of the HCl solution and the HC2H3O2 solution. You can use the formula M = moles/L to calculate the molarity.
You're welcome! I'm glad I could help you with your previous question. Now let's move on to calculating the molar concentration (molarity) of the HCl solution and the HC2H3O2 solution.
To calculate the molarity, we use the formula:
Molarity (M) = Moles (mol) / Volume (L)
For the HCl solution, you mentioned you had 5 mL of HCl. To convert this to liters, we divide by 1000:
Volume of HCl = 5 mL / 1000 = 0.005 L
Since you found that you had 5x10^-4 moles of NaOH, which is equal to the moles of HCl, we can substitute these values into the formula:
Molarity (HCl) = Moles (HCl) / Volume (HCl)
Molarity (HCl) = 5x10^-4 mol / 0.005 L
Now you can perform the calculation to find the molar concentration (molarity) of the HCl solution.
Similarly, for the HC2H3O2 solution, you'll need to know the volume of the HC2H3O2 solution and the number of moles of NaOH you used.
Please provide the volume of the HC2H3O2 solution and the number of moles of NaOH used, and I can assist you with the calculation.
To calculate the molar concentration (molarity) of the HCl solution and the HC2H3O2 solution, you need to use the formula:
Molarity (M) = Moles (mol) / Volume (L)
For the HCl solution, you mentioned that you used 5 mL of it. However, since the formula requires volume in liters, you need to convert 5 mL to liters by dividing it by 1000:
Volume (L) = 5 mL / 1000 = 0.005 L
For the moles of HCl, you already calculated it to be 5x10^-4 mol. So now, you can plug these values into the formula:
Molarity (HCl) = 5x10^-4 mol / 0.005 L
Simplifying the equation, you get:
Molarity (HCl) = 0.1 M
Similarly, for the HC2H3O2 solution, you need to know the volume in liters and the number of moles. However, you didn't provide the volume or moles for the HC2H3O2 solution in your question.
To find the moles of HC2H3O2, you need to know the volume and molarity of NaOH that you used for the reaction. If you have that information, you can use the same approach as mentioned before: multiply the volume in liters by the molarity to get the number of moles.
Once you have the moles of HC2H3O2, divide it by the volume of the HC2H3O2 solution in liters to calculate its molarity using the formula mentioned above.
Remember, it is important to provide all the necessary data (volume and molarity) in order to calculate the molarity accurately.