Consider a rectangular block of mass 30kg, height= 3m, length = 2m. A force F is applied horizontally at the upper edge. The acceleration of gravity is 9.8 m/s^2.
1)What is the minimum force required to start to TIP the block?
2)What is the minimum coefficient of static friction required for the block to tip with the application of a force of this magnitude?
Ok, you need the thickness. There are two things here: THe force at the top being countered by the righting moment. The righting moment is the weight of the block x the perpendicular distance to the piviot point (back of block edge). The perpenducular distance is normally 1/2 thickness of the block.
Force*Height= 1/2 mg*t/2
Now, for the force not to slide the block. mg(mu)=forceapplied
THANKS!!
To find the minimum force required to start tipping the block, we need to calculate the righting moment. The righting moment is the force at the top of the block countered by the weight of the block acting at some distance away from the pivot point.
The perpendicular distance from the weight of the block to the pivot point is usually taken as half the thickness of the block. However, since you did not provide the thickness, we will consider it as 't' for now.
The formula for the righting moment is:
Righting moment = Force * Height = (1/2) * m * g * (t/2)
Where:
- Force is the force applied at the upper edge of the block
- Height is the height of the block
- m is the mass of the block
- g is the acceleration due to gravity
- t is the thickness of the block (unknown value)
To find the minimum force required to start tipping the block, we need to consider the counteract force, which is the weight of the block multiplied by the coefficient of static friction. This force should be greater than or equal to the force applied.
The formula for the counteract force is:
Counteract force = m * g * (μs)
Where:
- m is the mass of the block
- g is the acceleration due to gravity
- μs is the coefficient of static friction (unknown value)
To find the minimum coefficient of static friction required for the block to tip with the application of a force of this magnitude, we need to equate both the righting moment and the counteract force.
So, we have:
(1/2) * m * g * (t/2) = m * g * (μs)
Canceling out the mass and the acceleration due to gravity, we get:
(1/2) * (t/2) = μs
Simplifying further, we have:
(t/4) = μs
Therefore, the minimum coefficient of static friction required for the block to tip with the application of a force of this magnitude is equal to one-fourth of the thickness of the block.
However, since you did not provide the thickness of the block, we cannot calculate the exact value of the minimum force or the minimum coefficient of static friction.