Posted by **Belle** on Sunday, April 22, 2007 at 5:34pm.

Consider a rectangular block of mass 30kg, height= 3m, length = 2m. A force F is applied horizontally at the upper edge. The acceleration of gravity is 9.8 m/s^2.

1)What is the minimum force required to start to TIP the block?

2)What is the minimum coefficient of static friction required for the block to tip with the application of a force of this magnitude?

Ok, you need the thickness. There are two things here: THe force at the top being countered by the righting moment. The righting moment is the weight of the block x the perpendicular distance to the piviot point (back of block edge). The perpenducular distance is normally 1/2 thickness of the block.

Force*Height= 1/2 mg*t/2

Now, for the force not to slide the block. mg(mu)=forceapplied

THANKS!!