# calculus

posted by
**mark** on
.

The base of a solid is a circle of

radius = 4

Find the exact volume of this solid if the cross sections perpendicular to a given axis are equilateral right triangles.

I have the area of the triangle (1/2bh) to be equal to 2sqrt(12)

(1/2 * 4 * sqrt12)

I don't know what to do next. If someone knows, I'd be very thankful.

there are like triangles that have vertical bases. They run parallel to the y-axis. The triangles form 2 triangles each that are symmetric to the x-axis.

The equation of the circle is:

x^2 + y^2 = 16

Thanks!